Shear strength in concrete joints
RESULT
Design value shear stress | Design shear resistance | Requirement |
vEdi (MPa) | vRdi (MPa) | vEdi ≤ vRdi |
0.89 | 1.06 | OK |
DETAILS OF CALCULATION
Notation and methodology according to clause 6.2.5 of EC2
vEdi (design value of the shear stress) = 0.89 MPa
vEdi = VEd / (z·bi) = 70000 / (225·350) = 0.89 MPa
where:
- z (inner lever arm) = 0.9 · d = 0.9 · 250 = 225 mm
vRdi (design shear resistance at the interface) = 1.06 MPa
vRdi = min [vRdi(1) ; vRdi(2)] = min[1.06 ; 4.5] MPa
where:
- vRdi(1) = c·fctd + ρ·fyd·(μ·sinα + cosα)
vRdi(1) = 0.4·1.2 + 0.0019·434.78·(0.7·sin90º+cos90º) = 1.06 MPa
with:- fctd (design tensile strength) = αct · fctk,0.05 / γc
fctd = 1 · 1.8 / 1.5 = 1.2 MPa
with:
fctk,0.05 = 0.7 · fctm = 0.7 · 2.56 = 1.8 MPa
fctm = 0,30 × fck(2/3) = 0,30 × 25(2/3) = 2.56 MPa - ρ = Asw / (s·bi) = 1.01 / (15·35) = 0.0019
- fyd = fyk / γs = 500 /1.15 = 434.78 MPa
- c = 0.4 ; μ = 0.7 (interface Rough, No dynamic loads)
- fctd (design tensile strength) = αct · fctk,0.05 / γc
- vRdi(2) = 0.5·v·fcd = 0.5 · 0.54 · 16.67 = 4.5 MPa
with:- v = 0.6 ·(1-fck/250) = 0.54
- fcd = αcc · fck / γc = 1 · 25 / 1.5 = 16.67 MPa